Table of Contents |
It is no surprise that using the linear approximation will produce some error.
The linear approximation error is the difference between the actual function value and the value obtained through the linear approximation.

or
is larger. With absolute value, the difference is nonnegative regardless.
EXAMPLE
Consider the function
near
. We’ll use the linear approximation to estimate
, then find the linear approximation error.
|
Use the equation for the tangent line. |
|
|
|
and
|
|
Simplify. |
.
is 0.1823 (to 4 decimal places).
.
. Use the linear approximation at
to estimate
. Then, find the linear approximation error to 4 decimal places.
In 3.4.1, we used
to approximate
for values of x near 16.
Here is a table of values (rounded to four decimal places) to illustrate what happens to the error as x moves away from 16:
| x |
|
|
Error
|
|---|---|---|---|
| 16.25 | 4.0313 | 4.0311 | 0.0002 |
| 16.5 | 4.0625 | 4.0620 | 0.0005 |
| 16.75 | 4.0938 | 4.0927 | 0.0011 |
| 17 | 4.1250 | 4.1231 | 0.0019 |
| 17.25 | 4.1563 | 4.1533 | 0.0030 |
| 17.5 | 4.1875 | 4.1833 | 0.0042 |
| 17.75 | 4.2188 | 4.2131 | 0.0057 |
| 18 | 4.2500 | 4.2426 | 0.0074 |
As you can see, even though the errors are relatively small, they are increasing as x increases from 16. We would see a similar pattern if x were to decrease from 16 (15.75, 15.5, etc.).
, the error gets larger as x gets further from a.
Source: THIS TUTORIAL HAS BEEN ADAPTED FROM CHAPTER 2 OF "CONTEMPORARY CALCULUS" BY DALE HOFFMAN. ACCESS FOR FREE AT WWW.CONTEMPORARYCALCULUS.COM. LICENSE: CREATIVE COMMONS ATTRIBUTION 3.0 UNITED STATES.