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Graphing Transformations of Tangent, Cotangent, Secant, and Cosecant Functions

Author: Sophia

what's covered
In this lesson, you will analyze the graphs of the remaining four trigonometric functions and their transformations. Specifically, this lesson will cover:

Table of Contents

1. Transforming the Graphs of the Secant and Cosecant Functions

Recall that sec   x equals fraction numerator 1 over denominator cos   x end fraction comma meaning that if the value of cos   x is known, then sec   x is its reciprocal.

Consider now this table of values.

bold italic x 0 straight pi over 6 straight pi over 4 straight pi over 3 straight pi over 2 straight pi fraction numerator 3 straight pi over denominator 2 end fraction 2 straight pi
bold italic y bold equals bold cos bold   bold italic x 1 fraction numerator square root of 3 over denominator 2 end fraction fraction numerator square root of 2 over denominator 2 end fraction 1 half 0 -1 0 1
bold italic y bold equals bold sec bold   bold italic x 1 fraction numerator 2 square root of 3 over denominator 3 end fraction square root of 2 2 undef. -1 undef. 1

Since sec   x equals fraction numerator 1 over denominator cos   x end fraction comma we can build the graph of the secant function from the cosine function, as shown in the figure below.

Properties of the graph:

  • There are vertical asymptotes at the same values where y equals cos   x has its x-intercepts.
  • The domain of y equals sec   x is the set of all real numbers excluding odd multiples of straight pi over 2.
  • The range of y equals sec   x is open parentheses short dash infinity comma space short dash 1 close square brackets union open square brackets 1 comma space infinity close parentheses.
  • The period is 2 straight pi.
  • Since the graph is not bounded, there is no amplitude.
Recall that csc   x equals fraction numerator 1 over denominator sin   x end fraction comma meaning that if the value of sin   x is known, then csc   x is its reciprocal.

Consider now this table of values.

bold italic x 0 straight pi over 6 straight pi over 4 straight pi over 3 straight pi over 2 straight pi fraction numerator 3 straight pi over denominator 2 end fraction 2 straight pi
bold italic y bold equals bold sin bold   bold italic x 0 1 half fraction numerator square root of 2 over denominator 2 end fraction fraction numerator square root of 3 over denominator 2 end fraction 1 0 -1 0
bold italic y bold equals bold csc bold   bold italic x undef. 2 square root of 2 fraction numerator 2 square root of 3 over denominator 3 end fraction 1 undef. -1 undef.

Since csc   x equals fraction numerator 1 over denominator sin   x end fraction comma we can build the graph of the cosecant function from the sine function, as shown in the figure below.


Properties of the graph:

  • There are vertical asymptotes at the same values where y equals sin   x has its x-intercepts.
  • The domain of y equals csc   x is the set of all real numbers excluding integer multiples of straight pi.
  • The range of y equals csc   x is open parentheses short dash infinity comma space short dash 1 close square brackets union open square brackets 1 comma space infinity close parentheses.
  • The period is 2 straight pi.
  • Since the graph is not bounded, there is no amplitude.
Now, let’s turn our attention to graphing transformations of the secant and cosecant functions, whose equations have the form y equals a   sec open parentheses b x minus c close parentheses plus d and y equals a   csc open parentheses b x minus c close parentheses plus d.

  • The value of a is not related to amplitude since the secant and cosecant graphs are not bounded. This value simply determines vertical stretch or compression, and a reflection over the x-axis if a less than 0.
  • Assuming b greater than 0 comma the period is fraction numerator 2 straight pi over denominator b end fraction.
  • The phase shift is c over b.
  • The vertical shift is d units, which means the midline is y equals d.
As you can see, except for amplitude, the process for transforming secant and cosecant graphs is similar to transforming graphs of the sine and cosine functions.

watch
In this video, we’ll walk through the transformations required to graph y equals 4 plus 3   sec open parentheses 2 x close parentheses.

try it
Consider the graph of y equals short dash 2 plus 5   sec open parentheses x plus straight pi over 6 close parentheses.
Determine the period, phase shift, and vertical shift.
Period: 2 straight pi
Phase shift: straight pi over 6 units to the left
Vertical shift: down 2 units
Write equations of two vertical asymptotes.
Two asymptotes of the graph of y equals sec   x are x equals short dash straight pi over 2 and x equals straight pi over 2.

Since this graph is shifted to the left straight pi over 6 units, the asymptotes are as well.

Then, subtract straight pi over 6 from each given value to find where the vertical asymptotes are:

short dash straight pi over 2 minus straight pi over 6 equals short dash fraction numerator 2 straight pi over denominator 3 end fraction

straight pi over 2 minus straight pi over 6 equals straight pi over 3

Thus, the equations of two vertical asymptotes are x equals short dash fraction numerator 2 straight pi over denominator 3 end fraction and x equals straight pi over 3.

Note: There are many other asymptotes.


2. Transforming the Graphs of the Tangent and Cotangent Functions

Before getting to the graphs of the tangent and cotangent functions, the figure below shows the unit circle with angles theta and theta plus straight pi.


Assuming that x not equal to 0 comma recall that tan theta equals y over x when the terminal side of angle theta intercepts the unit circle at the point open parentheses x comma space y close parentheses.

Then, for the angles theta and theta plus straight pi in the figure, we have tan theta equals y over x and tan open parentheses theta plus straight pi close parentheses equals fraction numerator short dash y over denominator short dash x end fraction equals y over x.

In general, this means that when tan theta is defined, then tan open parentheses theta plus straight pi close parentheses has the same value.

big idea
Since tan theta equals tan open parentheses theta plus straight pi close parentheses comma this means that the period of the tangent function is straight pi.

Note that the value of the tangent function is the slope of the line containing the points open parentheses 0 comma space 0 close parentheses and open parentheses x comma space y close parentheses.

watch
In this video, we’ll investigate the behavior of the tangent function as its input increases, particularly around values for which the tangent function is undefined.

Recall also that tan   x equals fraction numerator sin   x over denominator cos   x end fraction and that cos   x equals 0 when x is any odd multiple of straight pi over 2. Then, tan   x is undefined when x is any odd multiple of straight pi over 2.


The graph of the function y equals tan   x is shown below.


Properties of the graph:

  • There are vertical asymptotes at every value of x that is an odd multiple of straight pi over 2.
  • The domain of y equals tan   x is the set of all real numbers excluding multiples of straight pi over 2.
  • The range of y equals tan   x is open parentheses short dash infinity comma space infinity close parentheses.
  • The period is straight pi.
  • Since the graph is not bounded, there is no amplitude.
Also from the unit circle, recall that cot theta equals x over y when the terminal side of angle theta intercepts the unit circle at the point open parentheses x comma space y close parentheses.

Since these are reciprocal values of the tangent function, the basic cotangent function also has a period of straight pi comma meaning that cot open parentheses theta plus straight pi close parentheses equals cot theta comma as long as cot theta is defined.

Since cot theta equals fraction numerator cos theta over denominator sin theta end fraction comma the cotangent function is undefined for all values of theta where sin theta equals 0 comma or theta equals k straight pi comma where k is an integer.

All of this information considered, below is the graph of y equals cot   x. Even though it is not marked with a dashed line, there is also a vertical asymptote at x equals 0.

Properties of the graph:

  • There are vertical asymptotes at x equals k straight pi comma where k is an integer.
  • The domain of y equals cot   x is the set of all real numbers excluding integer multiples of straight pi.
  • The range of y equals cot   x is open parentheses short dash infinity comma space infinity close parentheses.
  • The period is straight pi.
  • Since the graph is not bounded, there is no amplitude.
Now, let’s turn our attention to graphing transformations of the tangent and cotangent functions, whose equations have the form y equals a   tan open parentheses b x minus c close parentheses plus d and y equals a   cot open parentheses b x minus c close parentheses plus d colon

  • The value of a is not related to amplitude since the tangent and cotangent graphs are not bounded. This value simply determines vertical stretch or compression, and a reflection over the x-axis if a less than 0.
  • Assuming b greater than 0 comma the period is straight pi over b.
  • The phase shift is c over b.
  • The vertical shift is d units, which means the midline is y equals d.
As you can see, except for amplitude and period, the process for transforming tangent and cotangent graphs is similar to transforming graphs of the sine and cosine functions.

watch
In this video, we’ll walk through the transformations required to graph y equals 3   tan open parentheses 2 x close parentheses.

try it
Consider the graph of y equals 1 plus 4   tan open parentheses 3 x close parentheses.
Determine the period, phase shift, and vertical shift.
The period is straight pi over b equals straight pi over 3.

There is no number added or subtracted in the angle, which means there is no phase shift.

The vertical shift is up one unit. We know this from the constant term.
Write equations of two vertical asymptotes.
The asymptotes correspond to where the angle is equal to short dash straight pi over 2 comma straight pi over 2 comma etc.

Therefore, set 3 x equals straight pi over 2 and 3 x equals short dash straight pi over 2 to get two of the vertical asymptotes. Solving each equation gives x equals short dash straight pi over 6 and x equals straight pi over 6.

Note: There are many other asymptotes.

summary
In this lesson, you learned that graphing transformations of the other trigonometric functions requires us to shift starting points, intercepts (when relevant), and asymptotes. Since none of these functions are bounded, there is no notion of amplitude. You learned that transforming the graphs of the secant and cosecant functions involves similar steps to transforming other functions, except there is no amplitude. In addition, you learned that transforming the graphs of tangent and cotangent functions is also similar, except there is no amplitude, and the period of the basic graphs is straight pi rather than 2 straight pi.

SOURCE: THIS WORK IS ADAPTED FROM PRECALCULUS BY JAY ABRAMSON. ACCESS FOR FREE AT OPENSTAX.ORG/BOOKS/PRECALCULUS/PAGES/1-INTRODUCTION-TO-FUNCTIONS