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The unit circle is a circle of radius 1 that is centered at the origin. Consider the graph below.
Using the Pythagorean theorem, , or more simply,
. This is true for any point on the unit circle. The equation of the unit circle is
.
Next, consider the figure below, which shows the unit circle and other information:
Every point corresponds to the length s of some circular arc. This means that x and y can be defined as functions of s, meaning s is the input, and x and y are outputs.
Now, how does the length s relate to the angle
Since and
we have
Thus, we can also express the sine and cosine function in terms of the angle, as well as its length.
To summarize, any point on the unit circle can be expressed as where
is the central angle of the arc; or
where s is the length of the arc. As you progress through this course, you will notice that using the angle as input becomes necessary to make more general definitions.
EXAMPLE
Consider the point PLet’s say that angle terminates at some ray that intersects the unit circle at some point
Then, any angle coterminal to
will also terminate at the same ray, which means the values of sine and cosine are the same as they were at the angle
This results in the following property.
Since a sine or cosine function can be applied to any angle, the domain of both functions is the set of all real numbers.
Considering all possible points on the unit circle, we see that and
Since and
for any point
on the unit circle, this means that
and
When substituting certain values of into the sine and cosine functions, we can refer to the unit circle to find these values. These special angles are:
Degrees |
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Radians | 0 |
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Let’s say we want the value of the sine function when the angle is You would write
when the angle is in radian form, which is equivalent to
when the angle is in degree form.
To start, let’s consider radians, which is also
Since and
when
it follows that
and
Along the same line of thinking, let’s now consider or in degrees,
Since and
when
it follows that
and
Now, let’s find the values at and
which are
and
respectively.
Now, consider the angle or in degrees,
Since it is easier to visualize, we’ll use degree measures to illustrate.
Consider this figure.
We know the following:
By using the Pythagorean theorem, we can find the value of x.
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This is the Pythagorean theorem. |
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Substitute the quantities. Since 1 is the hypotenuse, ![]() |
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Combine like terms. |
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Divide both sides by 2. |
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Apply the square root principle. |
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Since the point is in the first quadrant, use the positive solution. |
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Rewrite as a quotient of square roots and simplify the numerator. |
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Rationalize the denominator. |
This means that Since
it follows that
Thus, the terminal point on the arc of the circle is
which means
and
In radian form,
and
To summarize, we have the following table, which organizes the values of the sine and cosine functions for each special angle.
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0 |
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1 |
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0 |
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0 |
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1 |
Consider this picture below, which shows the signs of the coordinates in each quadrant:
Since and
we can make the following observations:
To evaluate trigonometric functions for angles that terminate outside the first quadrant, we need to use reference angles.
For the purposes of this exploration, let’s assume that angle terminates in quadrant I, and corresponds to the point
where x and y are positive. Our goal is to determine a relationship between
and the angles that correspond to the points
in quadrant II,
in quadrant III, and
in quadrant IV.
First, let’s examine a quadrant II angle.
Let be an angle that terminates in quadrant II, and corresponds to the point
as shown in the figure.
The cosines of the angles are opposites of each other since the x-coordinates are opposites. The sines of the angles are equal since the y-coordinates are equal.
Now notice the angle which has the same measure as
and is the smallest positive angle between
and the x-axis. If the coordinates are known in the first quadrant, then using
which is the reference angle, tells us the values of the coordinates in the second quadrant, since they have the same magnitude, but possibly different sign.
Seeing this now, here is a picture that shows what’s happening for angles that terminate in each quadrant. The formulas below each graph are used to calculate the reference angle in both degree form and in radian form.
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In each case, is the reference angle. Note that the measure of
is the same as the angle between the positive x-axis and the ray in the first quadrant each time.
EXAMPLE
Find the exact value ofEXAMPLE
Find the exact value ofHere is one more example, this time using an angle that terminates in quadrant IV.
EXAMPLE
EvaluateUsing the unit circle, we can define four more trigonometric functions, all based on the angle and point
on the unit circle:
With these definitions, let’s revert back to the unit circle to understand the domain of these functions. We’ll explore the range of these functions when we examine their graphs later in this course.
To examine the domains of these trigonometric functions, the information is organized in the chart.
Trigonometric Function and Its Ratio From the Unit Circle | Undefined at These Points on the Unit Circle |
Undefined for These Values of ![]() |
Domain of Function |
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All real numbers except for odd multiples of ![]() |
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All real numbers except all integer multiples of ![]() |
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All real numbers except for odd multiples of ![]() |
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All real numbers except all integer multiples of ![]() |
Taking all the formulas for these trigonometric functions and replacing x with and y with
we have the following identities.
There are six trigonometric functions total, but three of them are reciprocals of the other three. In practice, it is easier to find the values of sine, cosine, and tangent functions, then take their reciprocals to get the values of the cosecant, secant, and cotangent functions (as long as values are not undefined).
With all these definitions, we can find the values of all six trigonometric functions of an angle
EXAMPLE
Consider the point PUsing the values of and
at special angles, we can also find values of the other trigonometric functions.
EXAMPLE
Find the exact values of
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Use the identity ![]() |
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Simplify; multiply the numerator and denominator by 2. |
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Rationalize the denominator. |
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Use the identity ![]() |
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Simplify. |
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Rationalize the denominator and simplify. |
Using the relationships between the trigonometric functions and the coordinates on the unit circle, we can tell what the sign of the function value is simply by knowing the quadrant in which the angle terminates.
For example, consider the fact that If x and y have the same sign, then
If x and y have different signs, then
If we repeat this process for all six trigonometric functions and their defined ratios, we could summarize the results this way, listing where the functions return positive values.
Quadrant II (-, +) |
Quadrant I (+, +) |
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All functions are positive. |
Quadrant III (-, -) |
Quadrant IV (+, -) |
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If you want a mnemonic to remember this by, just remember All Students Take Calculus!
EXAMPLE
Find the exact value of
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Use the identity ![]() |
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Simplify; multiply the numerator and denominator by 2. |
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Rationalize the denominator. |
Consider the figure shown below, which shows that angle corresponds to the point
, while the angle
corresponds to the point
Let’s compare and
Since the value of the sine function is the y-coordinate of the point, we have
and
In general, we can say that
Is this true for all the trigonometric functions?
Let’s compare and
Since the value of the cosine function is the x-coordinate of the point, we have
and
In general, we can say that
Extending this to the other trigonometric functions, we can establish identities known as the even/odd identities.
Given a function recall that
is even if
and odd if
Therefore, the sine, cosecant, tangent, and cotangent functions are odd, while the cosine and secant functions are even.
These identities are useful to evaluate trigonometric functions of negative angles when the function value at the positive angle is known.
EXAMPLE
The even/odd identities are very useful when graphing trigonometric functions, which is covered in a future lesson.
SOURCE: THIS WORK IS ADAPTED FROM PRECALCULUS BY JAY ABRAMSON. ACCESS FOR FREE AT OPENSTAX.ORG/BOOKS/PRECALCULUS/PAGES/1-INTRODUCTION-TO-FUNCTIONS