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Quadratic equations written in vertex form provide readily available information about the the parabola it represents on a graph. The variables h and k form a coordinate pair (h, k) and represent the vertex of the parabola.
The vertex is the maximum or minimum point to the parabola (depending on if the graph opens upward or downward). Using the vertex form of quadratic equations can be ideal for graphing parabolas because we can easily identify the vertex, plot points on one side of the vertex, and then reflect them across the axis of symmetry on which the vertex lies.
Recall that the standard form of quadratic equations expresses the quadratic in expanded terms, containing an x-squared term, an x-term, and a constant term.
On the other hand, equations in vertex form resemble the factored form of a quadratic, with a linear binomial raised to the second power.
We can use a process called completing the square to write an expanded quadratic as a factor squared. In order to do this, our expanded quadratic must be a perfect square trinomial. In other words, half of the x-term coefficient squared is equal to the constant term.
EXAMPLE
Rewrite
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Half of 6 is 3. 3 squared is 9. This is a perfect square trinomial. |
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Perfect square trinomials can be written as a binomial squared. |
In order to rewrite a quadratic equation from standard form to vertex form, we need be able to recognize the perfect square trinomial relationship. Often times, this isn't readily provided to us, and we need to do some algebraic manipulation, with a process known as completing the square. You may have had some practice completing the square when learning about solving or factoring quadratic equations. To complete the square within this context, we perform the following steps:
There are quite a few steps involved in this process, so we are going to take a look at an example step-by step.
EXAMPLE
Rewrite the equation
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Move the constant term to the other side of the equation |
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Factor out the x-squared coefficient |
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Separately, divide the x-term coefficient by 2, and square it. |
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Add the quantity from the previous step to both sides of the equation. Don't forget to add the full value to the left side! |
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Recognize part of the expression as a perfect square trinomial and express it as a binomial squared |
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Isolate y by moving other terms to the other side of the equation |
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Our solution |
Now we have an equation equivalent to the equation given to us in standard form. If we were to graph the two equations, we would get the same parabola. However, you may prefer to work with the equation in vertex form, as this form gives the coordinates of the vertex (h, k).
Source: THIS TUTORIAL HAS BEEN ADAPTED FROM "BEGINNING AND INTERMEDIATE ALGEBRA" BY TYLER WALLACE. ACCESS FOR FREE AT www.wallace.ccfaculty.org/book/book.html. License: Creative Commons Attribution 3.0 Unported License